x=2x^2-18x+36

Solution for x=2x^2-18x+36 equation:

x=2x^2-18x+36

We move all terms to the left:

x-(2x^2-18x+36)=0

We get rid of parentheses

-2x^2+x+18x-36=0

We add all the numbers together, and all the variables

-2x^2+19x-36=0

a = -2; b = 19; c = -36;
Δ = b2-4ac
Δ = 192-4·(-2)·(-36)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{73}}{2*-2}=\frac{-19-\sqrt{73}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{73}}{2*-2}=\frac{-19+\sqrt{73}}{-4}
$